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x^2+5x-3=25-5x-4
We move all terms to the left:
x^2+5x-3-(25-5x-4)=0
We add all the numbers together, and all the variables
x^2+5x-(-5x+21)-3=0
We get rid of parentheses
x^2+5x+5x-21-3=0
We add all the numbers together, and all the variables
x^2+10x-24=0
a = 1; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·1·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*1}=\frac{-24}{2} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*1}=\frac{4}{2} =2 $
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